-3b^2+76b-25=0

Solution for -3b^2+76b-25=0 equation:

-3b^2+76b-25=0

a = -3; b = 76; c = -25;
Δ = b2-4ac
Δ = 762-4·(-3)·(-25)
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5476}=74$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-74}{2*-3}=\frac{-150}{-6}
=+25
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+74}{2*-3}=\frac{-2}{-6}
=1/3
$